Question

find the nature of the roots 3x²-2x+16=0​

Answer 1

Answer:

3x^2 - 2x + 16 = 0

Here,

co-efficient of x^2 (a) = 3

co-efficient of x (b) = - 2

co-efficient of x^0 (c) = 16

A.T.Q.

b^2 - 4ac

= (-2)^2 - 4×3×16

= 4 - 192

= - 188

Therefore,

The nature of the roots 3x^2 - 2x + 16 is not real root or imaginary root because b^2 - 4ac < 0.

Answer :- Not real root or Imaginary root

Answer 2

Step-by-step explanation:

i don't know......................................easy but hard