Question

find the nature of the roots find the nature of the roots of the following quadratic equation x square minus 2 root 3 x minus 1 equals to zero if real roots exist find them ​

Answer 1

Heyy

The answer is in the below attachment

Answer 2

Answer:

$x {}^{2} - 2 \sqrt{3} x - 1 = 0 \\ \\ discriminant = \sqrt({b} {}^{2} - 4ac) \\ \\ \sqrt{} (4 \times 3 + 4) = \sqrt{} 16 = 4 \\ \\ therefore \: root = - b + - 4 \\ 2 \sqrt{3} - 4 \\ \\ \\ and2 \sqrt{3 } + 4$