Find the nature of the roots for the quadratic equation: m2 + 6m + 9 = 0
Answers
Answer:
Changes made to your input should not affect the solution:
(1): "m2" was replaced by "m^2".
Step by step solution :
STEP
1
:
Trying to factor by splitting the middle term
1.1 Factoring m2-6m-9
The first term is, m2 its coefficient is 1 .
The middle term is, -6m its coefficient is -6 .
The last term, "the constant", is -9
Step-1 : Multiply the coefficient of the first term by the constant 1 • -9 = -9
Step-2 : Find two factors of -9 whose sum equals the coefficient of the middle term, which is -6 .
-9 + 1 = -8
-3 + 3 = 0
-1 + 9 = 8
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Equation at the end of step
1
:
m2 - 6m - 9 = 0
STEP
2
:
Parabola, Finding the Vertex
Answer:
2m + 6m + 9 = 0
Step-by-step explanation:
8m = -9
m = -9/8
therefore m is less than 0 , Hence ,the roots are imaginary.