find the nature of the roots of equation 2x²+3√2x-4=0
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Answer:
X=1/√2, -√2
Step-by-step explanation:
2x²+4√2x-√2x-4=0
2x(x+2√2)-√2(x+2√2)=0
(2x-√2)(x+2√2)=0
From here
2x-√2=0. | x+2√2=0
2x=√2. | x=-2√2
x=√2/2 | x=-2√2
x=1/√2 | x=-2√2
so solution is x=1/√2, -√2
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