Question

Find the nature of the roots of equation 2x²-root5x+1=0
Please answer my question its urgent please

Answer 1

Answer:

Discriminant=b^2-4ac

=(-√5)^2-4(2)(1)

=5-8=(-3)

D<0

Hence, it has no real roots.

Answer 2

Answer:

No Real Roots

Step-by-step explanation:

On Compare 2x² - √5x + 1 = 0 with  ax² + bx + c = 0,we get

a = 2 , b = -√5 , c = 1

Discriminant ( D ) = b² - 4ac

= ( -√5 )² - 4 × 2 × 1

= 5 - 8

= -3

Here, D < 0

∴ No real roots .

Therefore ,

The nature of the roots of the equation = No real roots.

Hope it helps!Brainliest it Bhai!