Math, asked by samridhi4591, 1 year ago

Find the nature of the roots of quadratic equation 3x² -4√3x +4=0.

Answers

Answered by InnocentGirl0
11

discriminant =  {b}^{2}  - 4ac
 = ( - 4 \sqrt{3} )^{2}  - 4 \times 4 \times 3 \\  \\  = 48 - 48 = 0
since D= 0

therefore, nature of the roots of given p(x) are real and equal
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