Question

find the nature of the roots of the equation 2 x square - 6 x+ 3 = 0​

Answer 1

Compare 2x²-6x+3=0 with

ax²+bx+c=0 , we get

a=2 , b = -6 , c = 3

Discreminant (D) = b²-4ac

= (-6)²-4×2×3

= 36 - 24

= 12

D > 0

Therefore,

Roots are real and distinct.

••••

Answer 2

The above answer is correct.

ax² + bx + c.
In the above quadratic equation,
Discriminant (D) = b² - 4ac

★Roots are real, if D ≥ 0.
★Roots are imaginary (non real), if D<0
★ Roots are equal, if D=0
★ Roots are Unequal, if D>0.

Thankyou!!!