find the nature of the roots of the following quadratic equation. If real roots exist find them
2x*-3x +5=0}
Bunti360:
yeah
acroding to equations?
b = x coefficient, a = x² coefficient, c = constant
and substitute b*-4ac ?
b²-4ac is the discriminent
substitute a,b,c in the formula b²-4ac
if the result is > 0, Roots are real and 2 different roots exist
if the result is = 0, Roots are real and equal
if the result is less than 0, The roots are imaginary
Kk tnx
Answers
Answered by
189
Hey there!
________________
2 x^2 - 3x + 5 = 0
Where,
a = 2
b = -3
c = 5
[ According to ax^2 + bx + c = 0 , we just compared the equation with this]
Now, we know,
D = b^2 - 4ac
D = (-3)^2 - 4 × 2 × 5
D = 9 - 8 × 5
D = 9 - 40
D = - 31
Now, we know,
If D is less than 0 ( D < 0 ) then no real roots exist.
________________
I Hope it's right and hope it helps you...!!!
________________
2 x^2 - 3x + 5 = 0
Where,
a = 2
b = -3
c = 5
[ According to ax^2 + bx + c = 0 , we just compared the equation with this]
Now, we know,
D = b^2 - 4ac
D = (-3)^2 - 4 × 2 × 5
D = 9 - 8 × 5
D = 9 - 40
D = - 31
Now, we know,
If D is less than 0 ( D < 0 ) then no real roots exist.
________________
I Hope it's right and hope it helps you...!!!
it means that there is no solution means parallel lines
Both the Answers are different and accurate in specific contents ^^" ! Thanks
:)
here D means???
Discriminant of The Quadratic Equation ! It's the number ( b² - 4ac ) taken from the Quadratic Form : ax² + bx + c = 0 ; which helps discriminate between whether the Roots obtained are "REAL" or "Not Real"
ohkk thank u so meand discriminant is written shortly as D
Answered by
134
Heya!!
-----------------------
Polynomial is 2x^2 - 3x + 5:
According to graphs of quadratic polynomials ; (ax^2 + bx + c)
If a is positive then graph is in upward parabolic structure while if a is negative then graph's parabola is in downward.
If polynomial is factorizable then curves cut x axis.
Vertex of the graph is (-b/2a, - D/4a)
-------------------------
If polynomial is 2x^2 - 3x + 5:
Graph's parabola opens upwards as 2 >0.
Since it's nt factorisable.. Hence it doesn't cuts X axis And haven't any real roots.
It means parabola is in upward of x-axis.
Vertex of graph = (3/4, 31/8)
Hope it helps u :)
-----------------------
Polynomial is 2x^2 - 3x + 5:
According to graphs of quadratic polynomials ; (ax^2 + bx + c)
If a is positive then graph is in upward parabolic structure while if a is negative then graph's parabola is in downward.
If polynomial is factorizable then curves cut x axis.
Vertex of the graph is (-b/2a, - D/4a)
-------------------------
If polynomial is 2x^2 - 3x + 5:
Graph's parabola opens upwards as 2 >0.
Since it's nt factorisable.. Hence it doesn't cuts X axis And haven't any real roots.
It means parabola is in upward of x-axis.
Vertex of graph = (3/4, 31/8)
Hope it helps u :)
ya
if we get -root value wt we have to do?
these type of questions r nt in 10th.. if u r in higher classes then use complex no concept
OK
I just entered into 10this year
I'm not perfect about topic so I'm going through
Kk
who r u?
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