Question

find the nature of the roots of the quadratic equation 13 root 3 X square + 10 X + root 3 is equal to zero answer in detail

Answer 1

nature of root can be determined by using the formula b^2 -4ac
here in the equation a=13root3
b=10 c=root 3
now putting in formula b^2 -4ac
(10)^2-4×13root3×root3
100-156= -56
so ans is negative that is less than zero
so roots are complex

pls mark it as brainliest

Answer 2

a = 13√3 , b = 10, c = 3  

b^2 – 4ac = (10)^2 – 4(13√3)(3)

= 100 – 156

= – 56  

As b^2 –4ac < 0

So, the equation has no real roots