Question

find the nature of the roots of the quadratic equation 13√3x2 + 10x+ √3 = 0

Answer 1

Answer:

∴ No real roots

Step-by-step explanation:

Given Equation is 13√3x² + 10x + √3 = 0.

Here, a = 13√3, b = 10, c = √3.

Discriminant (D) = b² - 4ac

                          = (10)² - 4(13√3)(√3)

                          = 100 - 156

                          = -56.

Here, D < 0. Therefore, there are no real roots.

Hope it helps!

Answer 2

13√3 x² + 10 x + √3 = 0

Comparing with a x² + b x + c = 0 ,we get :

a = 13√3

b = 10

c = √3

Checking the discriminant

b² - 4 ac

==> ( 10 )² - 4 (13√3)(√3)

==> 100 - 4 × 13 × 3

==> 100 - 4 × 39

==> 100 - 156

==> - 56

Since b² - 4 a c < 0

The roots are not real.

Answer : The equation has no real roots .

Hope it helps

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