Question

Find the nature of the roots of the quadratic equation 3x2 - 4 3x+6= 0

Answer 1

${\huge{\mathfrak{\red{G}{iven}}}}$

${3x^2 -3x +6=0}$

From this equation,
a = 3; b = -3; c = 6

${\huge{\mathfrak{\red{T}{o\:find}}}}$

The Nature of roots

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Nature of roots is measured by Discriminant.

-» D = ${b^2 - 4ac}$

-» D = ${(-3)^2-4(3)(6)}$

-» D = ${9-72}$

-» D = ${-63}$

Since, D < 0

The roots are not real

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