find the nature of the roots of the quadratic equation
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x^2 - 4x + 3 = 0
x^2 - x - 3x +3 = 0
x(x - 1) - 3(x - 1) = 0
(x - 1)(x - 3) = 0
The answer is x = 3,1 and their nature is real and distinct roots
If it helps you then please mark it as brainliest
x^2 - x - 3x +3 = 0
x(x - 1) - 3(x - 1) = 0
(x - 1)(x - 3) = 0
The answer is x = 3,1 and their nature is real and distinct roots
If it helps you then please mark it as brainliest
parulbhullar:
no it's wrong
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