Question

find the nature of the roots of the quadratic equation x2+x+1=0

Answer 1

Step-by-step explanation:

.618 & -0.618 are the roots of quadratic equation x2 - x - 1 = 0.

Answer 2

Answer:

step 1 Address the input parameters and values

Quadratic Equation : x2 - x - 1 = 0

step 2 Substitute a , b and c values in below formula

x =- b ± √b² - 4ac

2a

=-(-1) ± √(-12 - 4 (1) (-1))

2(1)

=1± √1 - 4 (1)(-1)

2

=1± √1 + 4

2

=1± √5

2

step 3 Solve the above expression for minus & plus values

x1 =1 + √5

2

=1 + 2.2361

2

x2 =1 - √5

2

=1 - 2.2361

2

step 4 By simplifying the above expressions for x1 & x2

x1 =3.2361

2

x1 = 1.618

x2 =-1.2361

2

x2 = -0.618