Question

find the nature of the roots of the quadratic equation xsq-6x+3=0​

Answer 1

Answer:

real and unequal

Step-by-step explanation:

d=b^2-4ac

= 36-4(3)(1)

= 36-12

= 24

d is greater than 0

means it's positive

so the name of the root is

real and unequal

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