find the nature of the roots of the quadratic equations 13root 3x^2+10x +root3=0
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a=13root3
b=10
c=root3
b^2-4ac=(10)^2-4 (13root3 )(root3)
=100-156
=-56
b^2-4ac < 0
therefore roots are imaginary
b=10
c=root3
b^2-4ac=(10)^2-4 (13root3 )(root3)
=100-156
=-56
b^2-4ac < 0
therefore roots are imaginary
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