Find the nature root of the following equation x square - 6x+ 10 =0
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2
Answer:
i)
x
2
−3x+5=0
a=2,b=−3,c=5
Discriminant, D=b
2
−4ac=9−40=−31
Since D<0, the roots are imaginary for the given equation.
ii)
3x
2
−4
3
x+4=0
a=3,b=−4
3
,c=4
Discriminant, D=b
2
−4ac=48−48=0
Since D=0, the roots are real and equal for the given equation.
3x
2
−4
3
x+4=0
a=3,b=−4
3
,c=4
x=
2a
[−b±
b
2
−4ac
]
x=
6
4
3
=
3
2
iii)
2x
2
−6x+3=0
a=2,b=−6,c=3
Discriminant, D= b
2
−4ac=36−24=12
Since D>0, roots are real but not equal.
x=
2a
[−b±
b
2
−4ac
]
x=
4
6±
12
x=
4
6±2
3
x=
2
3±
3
Step-by-step explanation:
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