Question

find the nature roots
x2-8x+16=0​

Answer 1

➲CORRECT QUESTION :

• Find the nature of roots : $\sf{x^2 -8x+16= 0}$

☯ GIVEN :

• $\bf{x^2 -8x+16 = 0}$

☯TO FIND :

• The nature of the roots.

☯ FORMULA REQUIRED :

• $\bigstar{\underline{\boxed {\red{\bf{D= b^2 -4ac}}}}}\bigstar$

➲SOLUTION :-

✞ We have,

• a = 1

• b = -8

• c = 16

Substituting the given values in formula :

$\leadsto {\tt{D= b^2 - 4ac}}$

$\leadsto {\tt{D= ( - 8)^2 - 4\times 1\times16}}$

$\leadsto{\tt{D=64 -64}}$

$\leadsto\underline{ \huge{\green{\boxed{ \bf{D =0}}}}}$

$\huge{ \pink{\therefore}}$ Here , D is equal to 0 so roots are real and equal.