Find the new pressure developed on a surface if force and area of contact both be doubled a) P1 = P2 b) P1 = P2/2 c) P1 = 2P2 d) P2 = 4P1
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QUESTION⤵️
Find the new pressure developed on a surface if force and area of contact both be doubled a) P1 = P2 b) P1 = P2/2 c) P1 = 2P2 d) P2 = 4P1
ANSWER ⤵️
Let the old pressure be P1 and new pressure be P2.
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Let the old force be F1 and new force be F2= 2F1
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Let the old area be A1 and new area be A2= 2A1
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We knew that,
Where P is pressure, F is force and A is the area where pressure is applied
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Case 1
P = P1
F = F1
A = A1
P1 = F1/A1
©©©©©©©©©©©©©©©©©©©©©©©©©©
Case 2
P = P2
F = F2
A = A2
P2 = F2/A2
©©©©©©©©©©©©©©©©©©©©©©©©©©
But as it is said that F2 = 2F1 and A2 = 2A1
©©©©©©©©©©©©©©©©©©©©©©©©©©
So,
P2 = (2F1/2A1)
==> P2 = F1/F2
But F1/F2 = P1
So,
P2 = P1
Hope you may got it
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