Question

Find the
nfind the nature of roots of x square + 5 x + 6 is equal to zero ​

Answer 1

Step-by-step explanation:

given equation

x square + 5x = -6

nature of roots :

$\sqrt{b {}^{2} } - 4ac$

here a=1 , b=5 , c=-6

root of 5 square - 4(1)(-6)

root of 25 - (-24)

root of 25+24

root of 49

7

here

the roots are distinct and real roots

Answer 2

$\huge \sf \color{purple}{\underline{\underline{Answer}}} :$

Roots are unequal and real.

$\huge \sf \color{purple}{\underline{\underline{Solution}}} :$

$= {b}^{2} - 4ac \\ \\ = {5}^{2} - 4 \times 1 \times 6 \\ \\ = 25 - ( - 24) \\ \\ = > 49$

Here , b²-4ac is greater than 0

hence , Roots are unequal and real.