Question

For any x,y R,xy> 0, then the minimum value of equals​

Answer 1

Answer:

it cannot be explained

Step-by-step explanation:

in case of real no, there are infite no.s between tow real nos. even  in between  0 and 1, there are unlimited real nos.

so a this question cannot be answered correctly.

if you have further query, do let me know. i will solve for you.

Answer 2

Step-by-step explanation:

Given For any x,y ∈ R,xy> 0, then the minimum value of equals                    2x / y^3 + x^3 y / 3 + 4y^2 / 9x^4

• So to find minimum value  AM ≥ GM
• If we consider p,q,r we get p + q + r / 3 ≥ (p.q.r)^1/3
•           Now 2x / y^3 + x^3y / 3 + 4y^2 / 9x^4  / 3  ≥  (2x / y^3 . x^3y/3 . 4y^2 / 9x^4)^1/3
•                                                                          ≥ (8/27)^1/3
•                                                                          ≥ (2^3 / 3^3)^1/3
•                        2x/y^3 + x^3y/3 + 4y^2 / 9x^4 / 3   ≥ 2/3
•                     So 2x / y^3 + x^3y / 3 + 4y^2 / 9x^4  ≥  2  

so the minimum value is 2

Reference link will be

https://brainly.in/question/17738770