Find the no. Of atoms present in 56g N2o
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56 in g and 2 in N o
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Molecular mass of N2O= 14*2+16= 28+16=44g
Therefore, 1 mole of N2O=44g
So, 1g=1/44 moles and 56g= 1/44*56 moles.
Therefore 56/44 moles will have 6.022*10^23*56/44 atoms. Which is Avogadro number*56/44 atoms of N2O.
No. of atoms= 56/44* NA (NA is Avogadro number)
No. of atoms ≈ 1.5NA
Therefore, 1 mole of N2O=44g
So, 1g=1/44 moles and 56g= 1/44*56 moles.
Therefore 56/44 moles will have 6.022*10^23*56/44 atoms. Which is Avogadro number*56/44 atoms of N2O.
No. of atoms= 56/44* NA (NA is Avogadro number)
No. of atoms ≈ 1.5NA
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