Find the no of carbon atoms in 80g of caco3
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1 mole of CaCO3 = 100 g = 6.023 x 10^23 atoms
80 g ------------------> x
100 x = 6.023 x 10^23 x 80
x = 6.023 x 80 x 10^21 = 481.84 x 10^21 atoms
80 g ------------------> x
100 x = 6.023 x 10^23 x 80
x = 6.023 x 80 x 10^21 = 481.84 x 10^21 atoms
GAUTI11:
Is this ri8
yeah
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