Question

Find the no. Of electron present in an 8g gold pin

Answer 1

Answer:

2.445×10²²

Explanation:

No of moles of gold is

n = W/M

n = 8/197

No of electrons in 8 g gold is

Ne = n × NA

Ne = 8/197 × 6.022×10^23

Ne = 2.445×10^22 electrons

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Answer 2

Answer:

193*10^22 electrons

Explanation:

molar mass = 197 g/mol

electrons per atom = 79

given mass = 8g

no of moles = given mass/molar mass

                    = 8/197

no of atoms in 8g gold = 8/197 x 6.023 x 10^23

no of electrons present in 8g gold = 8/197 x 6.023 x 10^23 x 79

                                                         = 193 x 10^22