Question

Find the no of electrons in 49 g of h2so4

Answer 1

150.5×10^23 no. of electrons

Answer 2

no of electrons present in 1 molecule of h^2so^4

=2(1)+1(16)+4(8)

=50 electrons.

no of moles in 49 g of h^2so^4

= 49/molar mass. [ molar mass =98g]

= 49/98

=0.5 moles.

Now,

no of molecules in 0.5 moles

=0.5*6.022*10^23

=3.011*10^23 molecules

Now,

no of electrons in 3.011*10^23 molecules.

=50*3.011*10^23

=150.55*10^23 electrons.