Question

find the no. of molecules of sodium bicarbonate present in 5.08 grams

Answer 1

mass of NAHCO3 is 84 . so no. of moles is 5.08/84. no.of molecules is (5.08/84)*6.023×10^23

Answer 2

Answer:

36424809.5238

Explanation:

Mass of NAHCO3=84 .

No. of moles=$\frac{5.08}{84}$

No.of molecules = $(5.08/84)*6.023*10^2^3$

                           =36424809.5238