Question

if oneof the zeroes of the cubic polynomial x^3+ ax^2 + bx + c is –1, then the
product of the other two zeroes is .plzz give detailed expl......n.ur reply is more valuable for me

Answer 1

Let k,l and m be the solutions of the polynomial ax³+bx²+cx+d

Then klm = -$\frac{d}{a}$

In the question product of solutions = -c = (Solution 1) x (Solution 2) x (-1)

⇒ product of other two solutions = $\frac{-c}{-1} =c$