Question

find the no of neutron in so4 -2​

Answer 1

Answer:

For Sulfer For Oxygen

Mass = p + n mass = p + n

32 = 16 + n 16 = 8 + n

n = 32 - 16 n = 16 - 8

n = 32 - 16 n = 16 - 8

n = 32 - 16 n = 16 - 8 n = 16 n = 8

n = 32 - 16 n = 16 - 8 n = 16 n = 8

n = 32 - 16 n = 16 - 8 n = 16 n = 8 Since, here are 4 atoms of oxygen

n = 32 - 16 n = 16 - 8 n = 16 n = 8 Since, here are 4 atoms of oxygen THEREFORE, no. of n = 4×8 = 32

n = 32 - 16 n = 16 - 8 n = 16 n = 8 Since, here are 4 atoms of oxygen THEREFORE, no. of n = 4×8 = 32 Total no. of neutron in so4

n = 32 - 16 n = 16 - 8 n = 16 n = 8 Since, here are 4 atoms of oxygen THEREFORE, no. of n = 4×8 = 32 Total no. of neutron in so4

n = 32 - 16 n = 16 - 8 n = 16 n = 8 Since, here are 4 atoms of oxygen THEREFORE, no. of n = 4×8 = 32 Total no. of neutron in so4 = 16 + 32

n = 32 - 16 n = 16 - 8 n = 16 n = 8 Since, here are 4 atoms of oxygen THEREFORE, no. of n = 4×8 = 32 Total no. of neutron in so4 = 16 + 32 = 48