find the no of neutron in so4 -2
Answers
Answer:
For Sulfer For Oxygen
Mass = p + n mass = p + n
32 = 16 + n 16 = 8 + n
n = 32 - 16 n = 16 - 8
n = 32 - 16 n = 16 - 8
n = 32 - 16 n = 16 - 8 n = 16 n = 8
n = 32 - 16 n = 16 - 8 n = 16 n = 8
n = 32 - 16 n = 16 - 8 n = 16 n = 8 Since, here are 4 atoms of oxygen
n = 32 - 16 n = 16 - 8 n = 16 n = 8 Since, here are 4 atoms of oxygen THEREFORE, no. of n = 4×8 = 32
n = 32 - 16 n = 16 - 8 n = 16 n = 8 Since, here are 4 atoms of oxygen THEREFORE, no. of n = 4×8 = 32 Total no. of neutron in so4
n = 32 - 16 n = 16 - 8 n = 16 n = 8 Since, here are 4 atoms of oxygen THEREFORE, no. of n = 4×8 = 32 Total no. of neutron in so4
n = 32 - 16 n = 16 - 8 n = 16 n = 8 Since, here are 4 atoms of oxygen THEREFORE, no. of n = 4×8 = 32 Total no. of neutron in so4 = 16 + 32
n = 32 - 16 n = 16 - 8 n = 16 n = 8 Since, here are 4 atoms of oxygen THEREFORE, no. of n = 4×8 = 32 Total no. of neutron in so4 = 16 + 32 = 48