find the no. of sides of a polygon the sum of whose interior angle is 10 right angle.
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Answered by
1
Answer:
Sum of interior angles of polygon =10 right angles =10×90
o
=900
o
(given)
But sum of interior angles of a polygon =(2n−4) right angles.
i.e.900=(2n−4)×90
o
⇒180n−360=900
⇒180n=900+360
⇒n=
180
1260
⇒n=7
Hence the required number of sides =7
Answered by
0
Sum of interior angles of polygon
=
10
right angles
=
10×
90
o
=
900
o
(given)
But sum of interior angles of a polygon
=
(2n−
4)
right angles.
i.e.900=
(2n−
4)×
90
o
⇒
180n−
360=
900
⇒
180n=
900+
360
⇒
n=
180
1260
⇒
n=
7
Hence the required number of sides
=
7
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