Question

find the no. of sides of regular polygon whose each interior angle has measured of 108°

Answer 1

interior angle = 108°

exterior angle = 180° - 108° = 72°

so, no of sides = 360° / 72° = 5

so, no of sides of polygon of 108° is 5 which is regular pentagon

Answer 2

Each exterior angle of the polygon is 108 degrees, so each exterior angle of the polygon is 180-108= 72 degrees. So the number of sides is 360/72 = 5. Hence it is a regular pentagon.