find the no. of terms of the ap 18,15 1/2,13,.....-49 1/2 and find the sum of all its terms
vinithanandanan:
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nth term of an AP=a + (n-1)*d
let -49.5 be the nth term.
here, a=18
d = 15.5 - 18 = -2.5
So, -49.5 = 18 + (n-1)*(-2.5)
solving this you get, n = 28.
Now sum of n terms of AP = n(a+l)/2
where l is the last term.
So, Sum of all terms = 28*(18 + (-49.5))/2
= -441
let -49.5 be the nth term.
here, a=18
d = 15.5 - 18 = -2.5
So, -49.5 = 18 + (n-1)*(-2.5)
solving this you get, n = 28.
Now sum of n terms of AP = n(a+l)/2
where l is the last term.
So, Sum of all terms = 28*(18 + (-49.5))/2
= -441
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