Find the no of zeros in 255 factorial + 88 factorial
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2
Answer:
83
Step-by-step explanation:
255! + 88! (no. of 0 depend on the no. of 5 and 2 )
Highest power of 2 in 255! :
255/2 + 255/4 + 255/8 + 255/16 + 255/32 + 255/64 + 255/128
127 + 63 + 31 + 15 + 7 + 3 + 1 = 247
Highest power of 5 in 255! :
255/5 + 255/25 + 255/125
51 + 10 + 2 = 63
So the no. of 0's in 255! is 63
Highest power of 2 in 88! :
88/2 + 88/4 + 88/8 + 88/16 + 88/32 + 88/64
44 + 22 + 11 + 5 +2 + 1 = 85
Highest power of 5 in 255! :
88/5 + 88/25
17 + 3 = 20
So the no. of 0's in 88! is 20
So the number of 0's in 255! + 88! = 63 + 20 = 83
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