Question

Find the normality of final solution ,if 300 ml if 1M Ca(OH)2 solution is mixed with 200 ml of 0.25 M Ca(OH)2 solution and the resulting solution is diluted to 1 Litre by adding water

Answer 1

ANSWER:

• Normality of the final solution = 0.7 N.

GIVEN:

• 300 mL of 1 M Ca(OH)₂ solution is mixed with 200 mL of 0.25 M Ca(OH)₂ solution.

• The resulting solution is again diluted to 1 L by adding water.

TO FIND:

• Normality of the final solution.

EXPLANATION:

Both are Ca(OH)₂ i.e of same nature.

$\boxed{ \bold{ \large{ \orange{M = \dfrac{M_1V_1 +M_2V_2}{V_1+V_2}}}}}$

$\sf\implies M_1 = 1\ M$

$\sf\implies M_2 = 0.25\ M$

$\sf\implies V_1 = 300\ mL$

$\sf\implies V_2 = 200\ mL$

$\tt \dashrightarrow M = \dfrac{1(300) +0.25(200)}{200 + 300}$

$\tt \dashrightarrow M = \dfrac{1(3) +0.25(2)}{2 + 3}$

$\tt \dashrightarrow M = \dfrac{3+0.5}{5}$

$\tt \dashrightarrow M = \dfrac{3.5}{5}$

$\tt \dashrightarrow Molarity = 0.7 \ M$

The resulting solution is again diluted to 1 L by adding water.

Molarity of dilution:

$\boxed{ \bold{ \large{ \purple{ M_1V_1 = M_2V_2}}}}$

$\sf\implies M_1 = 0.7\ M$

$\sf\implies V_1 = 300 + 200 = 500\ mL$

$\sf\implies V_2 = 1000\ mL$

$\tt \dashrightarrow0.7(500) = M_2(1000)$

$\tt \dashrightarrow0.7 =2 M_2$

$\tt \dashrightarrow M_2 = 0.35 \ M$

$\boxed{ \bold{\red{ Normality = Molarity \times Acidity}}}$

$\sf \implies Molarity =0.35 \ M$

$\sf \implies Acidity \ of \ Ca(OH)_2 = 2$

$\tt \dashrightarrow Normality = 0.35 \times 2$

$\tt \dashrightarrow Normality = 0.7\ N$

$\boxed{\pink{\sf{Normality\ of\ the\ final\ solution = 0.7\ N}}}$

Answer 2

$\huge{\underline{Question}}$

→ Find the normality of final solution ,if 300 ml if 1M Ca(OH)2 solution is mixed with 200 ml of 0.25 M Ca(OH)2 solution and the resulting solution is diluted to 1 Litre by adding water.

$\huge{\underline{Answer}}$

$Moles of HCl=$ $\sf{6×0.300+1×0.200=2\: mol}$

$\sf{Volume\: of\: the\: solution\: is\: 1 L}$

$sf{So,\: molar\: concentration\: of\: [H +]\: ion}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀$sf{=\: 12}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀${sf=2 M}$