find the nth term and 12th term of the sequence 2i, -6i , 18i,-54i....
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Answer:
In AP, is (i) represent iota?
or just an algebra term?
Step-by-step explanation:
OK OK , it's iota
GP= 2, 720....
Terms... Tn= ar^(n-1)
a=2, r= (720/2) or (6¡÷2¡) = 360
Tn= 2 × 360^ (n-1) = 720^(n-1)
and,
T12 = ar^(n-1)
T12 = 2 × 360^(12-1)
T12 = 2 × 360^(11)
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