Question

find the nth term and 6th e of GP 128,-96,72…​

Answer 1

Solution

Given :

a = 128

r = -96/128 = -3/4

nth term of GP is defined as the ar^(n-1)

⇒ aₙ = 128x(-3/4)⁽ⁿ⁻¹⁾

∴ 6th term =

⇒ ar⁵ = 128x (-3/4)⁵

= 31104/1024

= 243 / 8

∴ sixth term of the GP is 243 / 8