Math, asked by vegasg57, 9 months ago

find the nth term and 6th e of GP 128,-96,72…​

Answers

Answered by Acharya01
0

Solution

Given :

a = 128

r = -96/128 = -3/4

nth term of GP is defined as the ar^(n-1)

⇒ aₙ = 128x(-3/4)⁽ⁿ⁻¹⁾

∴ 6th term =

⇒ ar⁵ = 128x (-3/4)⁵

= 31104/1024

= 243 / 8

sixth term of the GP is 243 / 8

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