find the nth term and 6th e of GP 128,-96,72…
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Solution
Given :
a = 128
r = -96/128 = -3/4
nth term of GP is defined as the ar^(n-1)
⇒ aₙ = 128x(-3/4)⁽ⁿ⁻¹⁾
∴ 6th term =
⇒ ar⁵ = 128x (-3/4)⁵
= 31104/1024
= 243 / 8
∴ sixth term of the GP is 243 / 8
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