Question

find the nth term of an AP sum of whose first n term is 3n^2+2n

Answer 1

here your answer is in image and nth term is 6n-1

Answer 2

Here is your solution

Given as 

sn​=3n^2+2n 

To find out we need to find first term and Common difference 

Let n= 1

We got the first term a = 5

Now also put n=2 

Since it's the sum of 2 term =16

2nd term = S2 - a 
= 16 - 5 
= 11

Now we have 
a1 = 5 and a2 = 11

Now d = a2- a1 
d = 11 - 5 = 6

n term ​=a+(n-1)d
n term=5+(n-1)6
n term=5+6n-6
n term=6n-1

hope it helps you