Find the nth term of AP 3K, 5K, 7k,---
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a = 3k
d = 2k
an = a+(n-1)d
= 3k+(n-1)(2k)
= 3k+2nk - 2k
= k+2nk
an= k(2n+1)
Thus the nth term of the AP is k(2n+1)
d = 2k
an = a+(n-1)d
= 3k+(n-1)(2k)
= 3k+2nk - 2k
= k+2nk
an= k(2n+1)
Thus the nth term of the AP is k(2n+1)
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