Find the nth term of following AP *105,99,93 *4th term = 12, 7th term = 27
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a4 = 12
A + 3d = 12______(1)
a7 = 27
A + 6d = 27______(2)
Subtract (1) from (2) equation
A + 6d - ( A + 3d ) = 27 - 12
A + 6d - A - 3d = 15
3d = 15
d = 5
from (1) equation finding value of A
A + 3(5) = 12
A = 12 - 15
A = -3
now,
nth term = A + (n - 1) d
= -3 + (n-1) 5
= -3 + 5n - 5
nth term = 5n - 8 Ans.
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