find the nth term of given arithmetic progression A.P=3,1,-1,-3,-5......
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Hello there
nth term of any AP can be given by
T(n) = a + (n-1)d
Here
a= 3
d= 1-3= -2
Therefore
T(n) = 3 + (n-1)×-2
T(n) = 3 + -2n + 2
T(n) = 5 - 2n
nth term of any AP can be given by
T(n) = a + (n-1)d
Here
a= 3
d= 1-3= -2
Therefore
T(n) = 3 + (n-1)×-2
T(n) = 3 + -2n + 2
T(n) = 5 - 2n
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