Question

find the nth term of the ap x-1, x-2,x-3......

Answer 1

$a = x - 1 \\ common \: difference = - 1 \\ nth \: term = a + (n - 1)d \\ = (x - 1) - (n - 1) \\ x - n$

Answer 2

Heya friend,

Techy Prince here.

➡Thanks for asking this question.

➡Here is the required answer : -

➡The given term sequence is,

➡x-1, x-2, x-3.....

➡We will observe that,

➡The (x-) part of each term remains the same while the digit increases each time.

➡So,

➡The terms till 9th,

➡x-1, x-2, x-3, x-4, x-5, x-6, x-7, x-8, x-9...

➡So,

➡The ninth term = x-9

Hope my answer to your question will be helpful to you ny friend.