find the nth term of the sequence 5 8 11 14
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t1=5 ,t2=8,t3=11, t4=14
a=t1 =5
d=t1-t2=8-5
d=3
tn=a+(n-1)d
tn =5+(n-1)×3
tn=5+3n-3
tn =5+n
tn =5n tn =5
nth term is 5 .
I think it helps you.....
a=t1 =5
d=t1-t2=8-5
d=3
tn=a+(n-1)d
tn =5+(n-1)×3
tn=5+3n-3
tn =5+n
tn =5n tn =5
nth term is 5 .
I think it helps you.....
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