find the nth term of this quadratic sequence 3, 11, 25, 45 mathswatch please help i never know how to find the n^2 sequences
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Answer:
Below.
Step-by-step explanation:
Let n be the sequence number of a term:
n: 1 2 3 4
Term: 3 11 25 45
Differences: 8 14 20
Differences: 6 6 <- the 6 indicates a 3n^2.
3n^2: 3 12 27 48
Subtract
from Term: 0 -1 -2 -3
The last row is an Arithmetic sequence with first term 0 and common difference -1, so the nth term is
3n^2 + 0 + (n - 1)*-1
= 3n^2 - n + 1 (Answer).
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