Question

Find the number
9. Four times a certain number is as much less than 120 as seven times the number
greater than 102. Find the number.
10. Find four consecutive numbers, whose sumir​

Answer 1

Question 9 Solution -

Let us assume that the certain number is X .

Given equality condition -

Four times a certain number is as much less than 120 as seven times the number greater than 102.

This can be expressed algebraically as -

120 - 4x = 7x - 102

=> 11x = 222

=> x = ( 222/ 11 ) .

Thus , the required number is ( 222 / 11 ) .

________________________

Question 10 =>

Find four consecutive numbers, whose sum is 30 .

Solution -

Let us assume that the initial number is X.

Next consecutive number - ( x + 1 )

Next consecutive number - ( x + 2 )

Next consecutive number - ( x + 3 )

Sum of these numbers -

=> ( x + 1 ) + ( x + 2 ) + ( x + 3 )

=> 3x + 6 = 30

=> 3x = 24

=> x = 8 .

Thus , the consecutive numbers are 8, 9, 10 and 11 .

__________________________

Answer 2

$\large\bf\underline {To \: find:-}$

• we need to find the number.

$\large\bf\underline{Given:-}$

• Four times a certain number is as much less than 120 as seven times the number greater than 102

$\huge\bf\underline{Solution:-}$

• Let the number be x

❥ According to Question :-

Four times a certain number is as much less than 120 as seven times the number

greater than 102.

Four times a certain number is as much less than 120 = 120 - 4x

seven times the number greater than 102 = 7x - 102

↣120 - 4x = 7x - 102

↣120 + 102 = 7x + 4x

↣222 = 11x

↣ x = 222/11

↣ x = 20.18

hence,

The number is 20.18

$\rule{200}3$