Question

Find the number if eight times of it is added to its square, the sum so obtained is -16.​

Answer 1

Answer:

I have put the ans in the picture

Answer 2

Answer:

The number is -4.

Step-by-step explanation:

From the above question,

They have given :

We can use algebra to solve this problem.

Let x be the number.

We know that eight times of x added to its square is -16, so we can represent this using an equation:

                               8x + $x^2$ = -16.

We can solve for x by using the quadratic equation:

                                 x = (-8 ± √($-8^{2}$ - 4(1)(-16))/2(1).

After simplifying, we get x = -4.

1. Let x be the number.

2. We know that 8x + $x^{2}$  = -16,

so we can represent this using an equation:

                 8x + $x^{2}$ = -16.

3. We can solve for x by using the quadratic equation:

                 x = (-8 ± √($-8^{2}$ - 4(1)(-16))/2(1).

4. After simplifying, we get x = -4.

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