find the number of arrangements of 5 things taken out of 12 things in which one particular thing must always be included?
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jainsk03:
Hi! I have assumed that order doesn't matter. If it matters then we will use permutation instead of combination
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Step-by-step explanation:
First of all, we can see that 1 thing will be always fixed. Therefore we have to find 9C3 for other places. So, 9C3=9!/3!*6!
=84
But there are 4 places. So we can arrange these in 4! Ways
Therefore, total ways =84*4!
=84*24=2016
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