find the number of atoms for 9500g of iron
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Answered by
1
Atomic mass of Fe = 56 gms
56 g of Fe contains 6.022×10
23
number of atoms
Thus, 50 g of Fe contains
56
6.022×10
23
×50 number of atoms
= 0.537×10
24
Answered by
0
Answer:
170.113 mol
Explanation:
no of moles=mass/molar mass
molar mass if iron is 55.845g/mol
given mass=9500g
no of moles=9500/55.845=170.113 mol
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