find the number of atoms of each type present in 3.42g of cane sugar (c12h22o11)
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342 gram pf sugar contain 6.02×10^23 atoms
Then 3.42 contain 6.02× 10^23 ×3.42÷342
6.02×10^23 × 0.01 = 6.02×10^21
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Noreen1256:
Ni 12 carbon ka mass 144 as ga yaha ...
12 carbons h 1 carbon ka mass 12 so 12× 12 = 144
Isi tarha 22 hydrogen 1 hydrogen ka mass 1 so 1×22=22
And 11 oxygen h 1 oxygen ka mass 16 so 11×16=176
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☺ hogya sOlveston?
Solve?
ji thx mole concept mujhae difficult lagta hae so numericals jldi solve nhi hotae
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