find the number of atoms present in 5 gram of limestone (CaCO3)
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The molecular weight of calcium carbonate is 100 g.
10 g of calcium carbonate corresponds to 0.1 mole.
One molecule of calcuim carbonate contains 5 atoms. Hence, 0.1 mole of calcium carbonate will contain 0.5N
A
atoms. Here, N
A
is the Avogadro number.
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