Question

find the number of atoms present in 5 gram of limestone (CaCO3)​

Answer 1

Answer:

The molecular weight of calcium carbonate is 100 g.

10 g of calcium carbonate corresponds to 0.1 mole.

One molecule of calcuim carbonate contains 5 atoms. Hence, 0.1 mole of calcium carbonate will contain 0.5N

A

atoms. Here, N

A

is the Avogadro number.