Question

Find the number of atoms which are present into 0.00075 g of nitrogen

Answer 1

$\large{explanation}$

$no \: of \: atoms = \frac{given \: mass}{molar mass}$

molar mass if nitrogen=7+7=14u

given mass of nitrogen=0.00075g

$no \: of \: atoms = \frac{0.00075}{14u}$

$no \: of \: atoms = 5.357approx$