Find the number of brick each measuring 25 CM *12.5 CM *7.5 cm required to construct a wall 6m long ,5m high and 0.5 m thick, while the cement and sand mixture occupies 1/20 part of the volume of the wall
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Given wall dimensions as: 6 m long, 5 m high and 0.5 m thick.
⟹ volume of wall =6×5×0.5=15m
3
Given, cement and sand mixture occupies
20
1
of the volume of the wall.
Therefore, volume of the wall occupied by the bricks =(1−
20
1
) volume of wall =
20
19
volume of the wall
=
20
19
×15=14.25m
3
Now, volume of each brick =
100
25
m×
1000
125
m×
1000
75
m
So, the number of bricks required =
volume of each brick
volume of wall
=
100
25
m×
1000
125
m×
1000
75
m
14.25m
3
=6080
Hence, 6080 bricks of given dimensions are required to construct the wall
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