Question

Find the number of coins 2.4cm diameter and 2mm thick, to be melted ti form circular cylinder of height 12cm and diameter 6cm

Answer 1

Given:
Radius of coin(r)=2.4/2
=1.2cm
Height of coin(h)=2mm
=0.2cm
Radius of cylinder(R)=6/2
=3cm
Height of cylinder (H)=12cm
Solution-
No. of coins=volume of cylinder/ volume of coin
=pi*R^2*H/pi*r^2*h
=R^2*H/r^2*h
=3^2*12/1.2^2*0.2
=9*12/1.44*0.2
=108/0.288
=108000/288
=375

Answer 2

375 coins to be melted to form circular cylinder

Step-by-step explanation:

Diameter of coin = 2.4 cm

Radius of coin =$\frac{2.4}{2}=1.2 cm$

Thickness of coin = 2mm = 0.2 cm

Volume of coin = $\pi r^2 h = \frac{22}{7} \times (1.2)^2 \times 0.2$

Height of cylinder = 12 cm

Diameter of cylinder = 6 cm

Radius of cylinder = $\frac{6}{2}= 3 cm$

Volume of cylinder =$\pi r^2 h = \frac{22}{7} \times 3^2 ( 12)$

We are given that number of coins 2.4cm diameter and 2mm thick, to be melted ti form circular cylinder of height 12cm and diameter 6cm

So, No. of coins = $\frac{\frac{22}{7} \times 3^2 ( 12)}{\frac{22}{7} \times (1.2)^2 \times 0.2}=375$

Hence 375 coins to be melted to form circular cylinder

#learn more :

Find the number of coins 1.5cm in diameter and 0.2cm thick to be melted to form a right circular cylinder of height 15cn and diameter 6cm.

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